Thanks for the reply! Learning things here.
var area_mil = (sq_area_btw_groups / n_para) * 1550 * (0.018/spec_res);
Where does the 1550 and 0.018 come from? I’m not able to find them in IPC-2221A
Converting mm2 to mils2 for the formula
Converting the nickels resistance to copper
Basically pretending the nickel strip is a thinner copper track. So the exposed area and resistive losses are the same.
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Hey,
This is an interesting way in calculation ampacity. Have you found the calculator to be accurate? I see Section 6.2 in the IPC spec, and the equation there.
Accurate enough for DIY eFoil battery packs for sure
Would it be usable for copper sheets too? From my understanding copper is 3.5/4x more conductive. If I for example use 0.1mm copper for thickness, can I put in 0.35mm to get an accurate reading?
